Re: inheritance / overriding question

From:
"Heinz Ozwirk" <SPAMhozwirk@arcor.de>
Newsgroups:
comp.lang.c++
Date:
Sat, 3 Mar 2007 10:57:11 +0100
Message-ID:
<45e94679$0$15941$9b4e6d93@newsspool4.arcor-online.net>
"Michael" <michael5139@yahoo.com> schrieb im Newsbeitrag
news:45e94323$0$31090$5a62ac22@per-qv1-newsreader-01.iinet.net.au...

Hi All,

I have the following:

#include <iostream>

class BaseClass {
   protected:
       int var;
   public:
       void setVar(int var){
           this->var = var;
           std::cout << "using BaseClass\n";
       }
       virtual void showVar() = 0;
};

class ClassA : public BaseClass {
   public:
       void setVar(int var){
           this->var = var;
           std::cout << "using ClassA\n";
       }
       void showVar(){
           std::cout << "using ClassA var is " << var;
       }
};

int main(){
   BaseClass* base;

   base = new ClassA;

   base->setVar(12); //I know I have a magic number here, please ignore
this
   base->showVar();
}

why does base->setVar() call the function in the BaseClass, not the one in
ClassA? Shouldn't ClassA override the BaseClass function?


base is a pointer to BaseClass, so, except for virtual functions, only
functions of BaseClass can be called through this pointer. To call a
(overloaded) function in a derived class through a pointer to (one of) its
base classes, declare the function as virtual in the base class. For all the
compiler knows, base points to an instance of BaseClass, so only those
declarations matter. When the compiler calls base->showVar(), it doesn't
even know that showVar has been overridden somewhere.

HTH
    Heinz

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