Re: Is finalizing a virtual method possible in C++?

"Alf P. Steinbach" <>
Fri, 22 Feb 2008 14:05:28 +0100
* Kira Yamato:

On 2008-02-22 07:35:34 -0500, Pavel Lepin <> said:

Kira Yamato <> wrote in

So, I don't want to say too hestantly that it is
impossible to simulate the finalizing of virtual methods
and classes in C++.

Hence, I rather turn to the experts and ask if anyone
knows if it is possible to simulate them in any way?

This is a FAQ.


Yes. Thanks. But the FAQ does not say that finalizing method is
impossible. If in fact it did, then the answer is found. Instead, it
just proposes a "solution."

So let me try asking differently, has anyone gotten further with a
better solution than merely stating a comment?

There should be no reason to finalize a member function in C++.

But if you absolutely must it's not that difficult.

     class Base
     friend class Derived;
         struct OverrideTag {};
         virtual void foo( OverrideTag = OverrideTag() ) = 0;

     class Derived: public Base
         virtual void foo( OverrideTag = OverrideTag() ) {}

     class FurtherDerived: public Derived
         // Nix njet.
     // virtual void foo( OverrideTag = OverrideTag() ) {}

     int main()
         Derived o;;

However, chances are that if you do something like this then you're
thinking in Java, not in C++, using ideas that don't make sense in C++.

Cheers, & hth.,

- Alf

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