Re: help: derived class uses base class protect value

From:

Kai-Uwe Bux <jkherciueh@gmx.net>

Newsgroups:

comp.lang.c++

Date:

Mon, 24 Jul 2006 00:33:08 -0400

Message-ID:

<ea1ii4$8ag$1@murdoch.acc.Virginia.EDU>

tomy wrote:

Daniel T. wrote:

I pasted the code above into my gcc complier and it compiled just fine.
Are you sure that the code above is what you have?

Thanks for your post.
Sorry, I tried again the code above which actually do work. :-)

The original code is with template. And as below :

//******************************************************
template<class T>
class Base
{
protected:
int mutex;
};

template<class T>
class Foo : public Base<T>
{
public:
inline void bar(int v) { mutex = v;}

Try

inline void bar(int v) { this->mutex = v;}

or

inline void bar(int v) { Base<T>::mutex = v;}

BTW: the inline is redundant.

};

//****************test main***********
int main()
{
        Foo<int> foo;
        foo.bar(100);
        return 0;
}
//****************************************************
compiled result:

foo.cpp: In member function `void Foo<T>::bar(int)':
foo.cpp:13: error: `mutex' undeclared (first use this function)
foo.cpp:13: error: (Each undeclared identifier is reported only once
for each function it appears in.)
//*****************************************************

I wonder what happens with the TEMPLATE?

Templates is where some strange name-lookup issues kick in.

Best

Kai-Uwe Bux