Re: Re-creating free threaded objects in the face of multiple threads

From:
"Dilip" <rdilipk@lycos.com>
Newsgroups:
microsoft.public.vc.atl
Date:
12 Mar 2007 18:38:42 -0700
Message-ID:
<1173749922.874919.24090@n33g2000cwc.googlegroups.com>
On Mar 12, 8:11 pm, "Igor Tandetnik" <itandet...@mvps.org> wrote:

Yes, I guess it's possible. Just do CreateIOne(); ReleaseIOne(); then,
in this order.


Not sure I get this Igor. Doesn't that order create the interface
pointer and release it right away?

Actually, now that I think of it, the whole idea is not going to work.
It is possible for one thread to release and destroy the object, just as
another is calling a method on it.

This should be safe, but requires locking for the normal case:


Ah! I wanted to avoid that -- the problem is my application pumps
real time stock market data into a COM server and this method call
will probably called quite a few times. A lock on the normal flow
might cause unacceptable bottlenecks.

 void CallCOMWrapperMethod()
{
    for (;;) {
        IOne* pCopy = 0;
        Lock();
        pCopy = pOne_;
        pCopy->AddRef();
        Unlock();

        HRESULT hr = pCopy->CallThisMethod();

        Lock();
        pCopy->Release();
        if (FAILED(hr) && pCopy == pOne_) {
            // We need to recreate the object
            CreateIOne();
            ReleaseIOne();
        }
        Unlock();

        if (SUCCEEDED(hr)) break;
    }

}


In the worst case, I will go with this approach but I am sure I must
be missing something -- does that CreateIOne, ReleaseIOne order
releases the interfaces pointer right away?

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