Re: How to make this program more efficient?

From:
courpron@gmail.com
Newsgroups:
comp.lang.c++
Date:
Tue, 23 Sep 2008 09:36:59 -0700 (PDT)
Message-ID:
<b60ca82c-07ea-4ddd-965e-27187d358ca1@d45g2000hsc.googlegroups.com>
On 23 sep, 03:26, Jon Harrop <j...@ffconsultancy.com> wrote:

[...]

I say you will not and that you need a memory barrier writing the
pointer (and nothing more).


Assuming you mean "deterministic" when you say "consistent", I think you =

are

wrong. Even if both the reader and writer lock the pointer (which is
pointless if the operations are already atomic) there is still a race
condition. Specifically, the reader (thread 2) might read either the old =

or

new value.


You still make a confusion between locks and memory barriers.

You have to take care about the memory ordering problem, at least on
SMP architectures. Well, even on a monoprocessor architecture,
instruction can be reordered statically, by the compiler. You use
memory barriers to deal with these problems. In the case of static
reordering, the compiler will see the memory barriers and take them
into account (if it doesn't then I don't consider this compiler to
handle multithreading ).

[...]
void set(int n, int m)
{
  struct pair * volatile t = (struct pair *)malloc(sizeof(struct pair=

));

  t->i = n;
  t->j = m;
  /* Atomic pointer write. */
#ifdef LOCKING
   pthread_mutex_lock(&mutex);
#endif
  global = t;
#ifdef LOCKING
   pthread_mutex_unlock(&mutex);
#endif

}
[...]


In your set function, without the locks, the intructions can be
reordered either at runtime on a SMP architecture or by the compiler.
Let's say we are on a monoprocessor, and the compiler reorders the
instructions. Data dependence analysis won't prevent reordering like
this :

t->i = n;
global = t;
// what happens if a reader uses global here ?
t->j = m;

Here the unfortunate reader will see a correct value for i but an
incorrect one for j. To prevent things like this, you need memory
barriers (and not locks which are overkill for this case).

Alexandre Courpron.

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