Re: Pass View object to QThread

From:
misiek303 <maugustyniak303@gazeta.pl>
Newsgroups:
comp.lang.c++
Date:
Sun, 03 Jan 2010 17:54:34 -0600
Message-ID:
<hhrant$kr6$1@inews.gazeta.pl>
I've just discovered that actually this code

Temperature::Temperature( QObject * parent ) : QThread( parent ) {
    View *view = dynamic_cast<View*>(parent);
    cout << view->currentTemperature << endl;
}

prints out correct value from view->currentTemperature

but the Thread which run the "run()" function prints out the pointer

void Temperature::run() {
    while(true) {
        cout << view->currentTemperature << endl;
        sleep(1);
    }
}

I defined view in the class here:

class Temperature : public QThread {
    Q_OBJECT

public:
    View *view;

what I am missing ??

I have one more question:

so I the View class as a QMainWindow, then in View I start Temperature
object as a QThread and pass the View to the Temperature that way

View *view = static_cast<View*>(parent);

so in View I have e Slot "whatever" with the code below

Temperature *t = new Temperature(this);
t->start();

"this" is the View object

in construct of the Temperature I have

View *view = static_cast<View*>(parent);

so I have now my View available in view inside Temperature class.

The point is that I got something weired. I've defined lets say int
variable VALUE in View which is = 100;

I would like to print it from Temperature so I do

View *view = static_cast<View*>(parent);
cout << view->VALUE << endl;

and here that weird, it doesn't print 100 value only 33 always, I am
guessing its a pointer, number is to short for the pointer but I guess it is

so why I don't have my 100 value ??

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