Re: NRVO or I think so

Hi,

I have a very simple class :

class Foo
{
        private :
            int m_nVal;
        public:
            Foo () {cout << "Constructor..." << endl;}
            Foo (const Foo&) {cout << "Copy constructor..." << endl;}
            ~Foo () {cout << "Destructor..." << endl;}

            void setter (int nVal) {m_nVal = nVal;}
};

And some code using this class :

1 Foo getFoo ()
2 {
3 Foo foo_1;
4
5 foo_1.setter (11);
6
7 return foo_1;
8 }
9
10 int _tmain (int argc, _TCHAR* argv [])
11 {
12 Foo foo = getFoo ();
13 return 0;
14 }

I expeced this output :

Constructor... (For line 3)
Copy constructor... (For line 7, a temporary object is copy-constructed from
foo_1)
Destructor... (For foo_1)
Copy constructor... (For line 12, foo is copy-constructed from the temporary
object)
Destructor... (for foo)
Destructor... (for the temporary object)

but the real output is (using Visual Studio 2008 compiler with debug
configuration) :

Constructor...
Copy constructor...
Destructor...
Destructor...

When I checked the assemby out I see address of the foo pushed into the
stack and used directly in getFoo () rather than creating a new temporary.
This is the optimization named NRVO, isn't this?
But I am compiling in debug configuration and optimizations are disabled,
why the compiler apply NRVO and how can I deactivate NRVO?