Re: Multiple operator overloading

James Kanze <>
Mon, 8 Nov 2010 04:46:23 -0800 (PST)
On Nov 8, 7:29 am, Stuart Redmann <> wrote:

"Daniel T." writes:

Your throwing away information that you will need later.
That's why it is a poor design in general. Don't throw
away information that you will need later.

I disagree. Having to work with several dictionaries (one for each
type) seems a much poorer decision to me. I'd prefer the boost::any
solution (actually I use this solution, although I try to avoid
boost::any as best as I can).

It depends on the context. If your data is initially two
different types, and will always be two different types, it
makes sense to maintain the type information. Usually, however,
when I've used something like this, my data comes from (and goes
into) a configuration file, where everything is a string. The
map in the object is also string to string, and it's only when
actually reading the data that it will be converted to the
desired type (with an exception if the conversion doesn't work).


No language I know provides such a feature that the return type is
somehow determined by the type of the variable the function call is
assigned to.

I know of one: C++. But only for conversion operators. See my
example using a proxy.

James Kanze

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