Re: where __declspec(dllexport) is defined?

"Ben Voigt [C++ MVP]" <rbv@nospam.nospam>
Fri, 26 Dec 2008 17:53:46 -0600
"GiuseppeDini" <> wrote in message

On 9 Dic, 22:11, "Doug Harrison [MVP]" <> wrote:

On Tue, 9 Dec 2008 13:04:10 -0800 (PST), GiuseppeDini <>

I created a dll project named "test" and I've found this code:

#define TEST_API __declspec(dllexport)
#define TEST_API __declspec(dllimport)

There is one thing i can't understand.
Where is TEST_EXPORTS defined when the code is compiled in the dll to
be exported?
I can't find a line where it is defined.

Look in your preprocessor options (/D).

Thank you.
I understand that it is a basic knowledge, but I'm new to c++.

I've noticed several names for that option:
So my application is also defined for win32. If I select a win64
project, the same code will run under a 64bit processor and one of the
above options will become WIN64?
(but I have vc++ express and I can't try it)

I think 64-bit builds define *both* WIN32 and WIN64 (and maybe also _WIN32
and _WIN64)


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