Re: Is it possible to catch an exception raised by a member variable?

From:
 James Kanze <james.kanze@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Fri, 28 Sep 2007 22:38:45 -0000
Message-ID:
<1191019125.839397.209160@n39g2000hsh.googlegroups.com>
On Sep 28, 11:30 am, "Chris ( Val )" <chris...@gmail.com> wrote:

On Sep 28, 7:03 pm, James Kanze <james.ka...@gmail.com> wrote:


    [...]

But you still don't have an object. You can use function try
blocks to remap the exception, or to treat it as a fatal error
(e.g. by calling abort or exit), but you cannot return normally
from the constructor, and the object that was being constructed
will not exist.


I have produced a crude example that will attempt to
prove otherwise:

# include <iostream>
# include <string>
# include <exception>

struct DataSource {
  DataSource( std::string ds )
   {
    if( ds != "Oracle.driver.foo" )
        throw "Could not connect to database";
   }
 };

class Base
 {
  private:
    DataSource Ds;
  public:
    Base( std::string );
    ~Base() { std::cout << "Destructing now...\n"; }
    void Print()
    { std::cout << "I am still alive - Please try again.\n"; }
 };

Base::Base( std::string ds )
try // function-try block
 : Ds( ds ) {}
catch( const char* msg ) {
  std::cout << "Exception Caught: \"" << msg << "\"" << '\n';
  throw std::exception();
 }

int main()
 {
  Base* B;

  try {
   B = new Base( "Oracle.driver.bar" );
  }
 catch( const std::exception& e )
  {
   B->Print();


This is undefined behavior, since it accesses an uninitialized
pointer. If you get here, the assign in the try block has never
occured (and there is no Base object).

   delete B;
  }

  std::cin.get();
  return 0;
 }

I am interested to hear your, and the groups
thoughts on the validity of such a construct.


Totally invalide.

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James Kanze (GABI Software) email:james.kanze@gmail.com
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