Re: Integer template argument warning

From:

"Ben Voigt [C++ MVP]" <bvoigt@newsgroup.nospam>

Newsgroups:

microsoft.public.dotnet.languages.vc

Date:

Sun, 12 Jul 2009 10:52:47 -0500

Message-ID:

<u3VlEkwAKHA.2604@TK2MSFTNGP03.phx.gbl>

"user790" <user790@gmail.com> wrote in message
news:e0680321-be83-4a5b-9d1a-ef81d10e501c@p29g2000yqh.googlegroups.com...

On Jul 6, 9:37 pm, "Ben Voigt [C++ MVP]" <r...@newsgroups.nospam>
wrote:

Ah, but it isn't converted to int until after the negation operator is
applied. Hence the problem, and the solution.

Right now you have

B<-I>

which is effectively

B<(int)(-I)>

Instead use

B<-(int)I>

Thanks for your response. However, I can't quite get your solution to
work. Replacing foo with

template < int I >
B<-(int)I> foo(A<I> const &)
{
return B<-(int)I>();
}

yields

error C2893: Failed to specialize function template 'B<-I> foo(const
A<I> &)'

at the line where I previously had a warning.

Do you have a prototype or other definition of foo anywhere? I don't see
why it should be trying to specialize anything.

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