Re: Avoid implicit cast from enum to double

From:
"Victor Bazarov" <v.Abazarov@comAcast.net>
Newsgroups:
comp.lang.c++
Date:
Tue, 18 Jul 2006 08:46:12 -0400
Message-ID:
<e9il6m$hn4$1@news.datemas.de>
Flo wrote:

I have the problem, that the following Code produces neither warning
nor error at compile time, at least not with the Microsoft Visual C++
6.0 compiler (warning level 4)

enum E { eOne, eTwo };
struct S {
 void fooDouble( double ) {};
 void fooEnum( E ) {};


Please drop the habit of appending a semicolon after a function body.
It just looks sloppy.

};
int main() {
 S s;
 s.fooDouble( eOne ); // neither warning nor error
 return 0;
}

As you can see, accidentally an enum is passed to the method expecting
an double. In my real program, this leads to an error at run-time,
since fooDouble only accepts quit small values, i.e. values smaller
than 1.0. Has anybody an idea what I can do, maybe changes in the
methodnames/parameterlist, to provoke a warning at compile time so one
can not accidentally pass an enum to the method expecting a double?


Wrap your enum in a struct and pass the struct. Inside just access the
wrapped value.

Check the value (or assert if you can debug all cases of using your
function) inside your 'fooDouble' function.

Be careful and just don't write code that passes the enum to 'fooDouble'.

V
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