Re: string comparision

From:
"Victor Bazarov" <v.Abazarov@comAcast.net>
Newsgroups:
comp.lang.c++
Date:
Tue, 18 Jul 2006 14:49:14 -0400
Message-ID:
<e9jafd$omt$1@news.datemas.de>
priyanka wrote:

I am trying to compare two strings. But I am not able to do so. I use

if(function_name[function_number] == function_label[k]){

but this does not work.


What does it mean "does not work"? Does not compile? Misbehaves? What?

I have written down my code:

const char *function_name[(code_addr_t)code_size];
string function_label[(code_addr_t)code_size];
int function_number = 0;
int i = 0;

ifstream inputStream("no_args.txt");
if(!inputStream)
   die();

while(!inputStream.eof())
   {
       getline(inputStream,funcName);
       i++;
       function_label[i] = funcName;


You are missing the zeroth element of the 'function_label' array. Is
that on purpose? Perhaps you inteded to use this idiom:

       function_label[i++] = funcName;

instead of the two lines above.

   }

int tot_func = i;


You're using a misnomer here. 'i' is the last index, not the total
number of the function names.

function_number = function_number + 1;


Why are you adding 1 here?

function_name[function_number] = "sumarray";


You're introducing undefined behaviour right here, if your 'function_number'
is larger than (code_size - 1). Just a thought...

for(int k = 1; k <=tot_func;k++){


In C++ indexing is done from 0 to (size-1). What book are you reading
that doesn't explain that simple feature?

if(function_name[function_number] == function_label[k]){
printf("inside if\n");

}

The execution never enters inside the if { printf("insde if\n");


How do you know? Did you debug your program? What does your 'no_args.txt'
file contains? Are you sure there is at least one occurrence of "sumarray"
string in there?

V
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