Re: Printing out function name

From:
=?UTF-8?B?RXJpayBXaWtzdHLDtm0=?= <Erik-wikstrom@telia.com>
Newsgroups:
comp.lang.c++
Date:
Thu, 25 Oct 2007 17:56:31 GMT
Message-ID:
<jN4Ui.12222$ZA.8028@newsb.telia.net>
On 2007-10-25 18:59, hodges.r@gmail.com wrote:

On Oct 25, 5:40 pm, Travis <travis.bow...@gmail.com> wrote:

On Oct 25, 9:12 am, Keith Willis <m...@privacy.net> wrote:

On Thu, 25 Oct 2007 16:02:05 -0000, Travis <travis.bow...@gmail.com>
wrote:

Is there a way to print out the name of the function calling another
function? For example:

void foo()
{
debugPrint("Beginning calculation...");
}

void debutPrint(string text)
{
cout << SOMETHING << text << endl;
}

so that i would get something like

"(foo) Beginning Calculation..."


void foo()
{
        debugPrint(__FUNCTION__,"Beginning calculation...")

}

void debugPrint(string func, string msg)
{
        cout << "(" << func << ") " << msg << endl;

}

Would that do it?
--
PGP key ID 0xEB7180EC


Yeah that's actually what i have implemented now. The __FUNCTION__
thing is great but is a gcc/g++ only thing right? I was more curious
if there was a c++ thing I wasn't aware of.- Hide quoted text -


I have used __FUNCTION__ in microsoft vc++


I thought __FUNCTION__ was VC and __func__ gcc. Anyway, in the next
version of the standard it will be __func__ (which I personally do not
like since it it is not similar to __LINE__ and __FILE__) as in C.

--
Erik Wikstr??m

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