Re: question about erase() function on a container
subramanian100in@yahoo.com, India wrote:
Suppose I have
vector<int> container;
Suppose I store some values into "container".
Suppose that "left" and "right" are valid iterators into
"container" and that "right" is NOT container.end() and
"right" comes after "left".
Given this, suppose
vector<int>::iterator iter = container.erase(left, right);
then "iter" will always be a copy of "right" iterator.
ie
if (iter == right) will always be true. Am I correct ? The same is
true for deque and list also. Is this correct ?
No.
After the erase, right is invalid, and any attempt to use it
(including comparing it with iter) is undefined behavior. With
g++, in debug mode, it crashes---I would expect this to be the
case with any quality implementation.
Given a standard library container, can we call clear() function on
empty container ? Or will it invoke undefined behaviour ?
You can always call clear(), on any container.
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