Re: Virtual destructor problem
On Apr 24, 7:59 am, GAURAV AGRAWAL <g...@buffalo.edu> wrote:
Can someone please explain me why this is happening
#include<iostream>
using namespace std;
class a {
public:
int a1; // If I remove this it'll work fine
a() {
cout << "Constructor of a \n";
}
~a() {
cout << "Destructor of a \n";
}
};
class b : public a{
public:
b() {
cout << "constructor of b \n";
}
virtual ~b() { // If I remove virtual from here ... it'll work fine
cout << "destructor of b\n";
}
};
int main() {
a *p = new b;
delete p;
return 0;
}
Result is :
Constructor of a
constructor of b
Destructor of a
a.out(1563) malloc: *** error for object 0x100154: Non-aligned pointer
being freed
*** set a breakpoint in malloc_error_break to debug
----------------------------------------------------------------
I know that if I'll put virtual in front of the destructor of
the base class code will work fine. But, I want to use it the
above way. Can someone please explain me the reason behind
this kind of behavior?
Simple. It's undefined behavior. So the compiler can assume
that you don't do it, and not take any steps that would
otherwise be necessary for it to work. The standard is very
clear about this: for a non-array delete, either the dynamic
type is the same as the static type, the destructor is virtual,
or you have undefined behavior. (For an array delete, the
dynamic and static types must be the same, period.)
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