Re: template class constructor shall be called from the initializer list of the inheriting, non-template class constructor

From:
Alberto Ganesh Barbati <AlbertoBarbati@libero.it>
Newsgroups:
comp.lang.c++.moderated
Date:
Mon, 17 Nov 2008 01:27:09 CST
Message-ID:
<Qd3Uk.104926$Ca.21522@twister2.libero.it>
Joe Smith ha scritto:

Daniel Kr??gler wrote:

14.6.1 [temp.local]/3 (in N2798, which is p.2a in 14882:2003(E))
says that the injected-class-name A can be used "wherever it is
in scope". It is available in scope of derived classes and
therefore your notation should be unambiguous and well-formed.

If your compiler does not accept it, you should use A<int>
instead of A in the scope of B (personally I would prefer this
anyway in this context).

HTH & Greetings from Bremen,


The 14882:2003(E) standard gives the following example in that section:

template <class T> struct Base {
Base* p;
};
template <class T> struct Derived: public Base<T> {
typename Derived::Base* p; // meaning Derived::Base<T>
};

This does get accepted by GCC.


That's good news ;)

However, the folowing, does not:

template <class T> struct Base {
Base* p;
};
struct Derived: public Base<int> {
Derived::Base* p; // meaning Derived::Base<T>
};

Is that supposed to work?


Yes. Daniel Kr??gler provided a good explanation for that.

GCC rejects both it and the OP's code.


:( That's a pity. Both Comeau Online and VS2005 accept both this code
and the OP's code.

Also if either the above or OP's code is supposed to work,
then somebody really ought to file a bug report against gcc.


Yes, I do believe a bug report should be filed for GCC.

HTH,

Ganesh

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