Re: overloading address operator and standard containers

From:
"Alf P. Steinbach" <alfps@start.no>
Newsgroups:
comp.lang.c++
Date:
Thu, 22 Oct 2009 21:46:04 +0200
Message-ID:
<hbqcpu$tta$1@news.eternal-september.org>
* Kai-Uwe Bux:

Hi folks,

please consider:

#include <list>

struct aaa {};

struct bbb {

  aaa operator & ( void ) const {
    return aaa();
  }

};

int main ( void ) {
  std::list< bbb > a;
}

Is this required to compile or is a compiler within its rights to reject the
code?


It can reject the code.

I'm sure you can find the standard's requirements yourself, so I just mention
the infamous case of Microsoft's ATL workarounds for this issue. They originally
designed the ATL library with address operators overloaded, incompatible with
the standard C++ library. So now you know that it's real issue you can safely
invest the time to find the standard's requirements (if u still feel u need it).

I recently posted a bug report and have been told that the code is invalid.
The address operator is supposed to be not overloaded. This, I have learned,
should follow from the provisions in C++03 about allocator::address().


Uh, it's that way also in C++98.

I am
still trying to understand the reasoning, but I feel that I need some help.


Part of the reasoning is, I think, that with overloaded address operator any
container that does low-level things has to do CounterIntuitive Things(TM) to
obtain the real address of an object.

Say, you have a raw array of formal type T[n], where the first k elements are in
use, and you want to emplace an object at a[k]. With the T address operator
overloaded you can't just do ::new(&a[k])T(args). You have to do silly things
such as ::new(&reinterpret_cast<void&>(a[k]))T(args). Or, well, I guess you
could do ::new(a+k)T(args), but it's a bother when a+k and &a[k] mean two
different things. And presumably the standard library code shouldn't have to
guard against this...

The Boost library has some wrapper for the reinterpret_cast.

Cheers & hth.,

- Alf

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