Re: Passing Two-Dimensional Array as a Function Parameter
On 2010-10-01 18:28:23 -0400, Jason S said:
I'm working on a program and have encountered a bit of an issue with
getting my program to work correctly. When I print the array in main(),
the values print out correctly. But when I debug the program to print
out their values in the calculatesquares(int[][], int. int) function,
they come out as very large integers. I assume they might be memory
addresses? Here's the code:
I haven't been through the code, but in general, if you suspect that
parameters aren't coming in the way you expect, the thing to do is
examine what's being passed and what you get. So copy the code from
main that displays the contents of the square into calculatsquares and
run it. If the arguments are coming in wrong, you know where to look.
If they're coming in right, you've got a base to work from.
int calculatesquares(int squares[][5], int r, int c)
{
int valsAcross[5];
int valsDown[5];
int valsDiag[2];
int xAcross, xDown, xDiag;
int works = 1;
for (int i = 0; i < 5; i++)
{
for (int j = 0; j < 5; j++)
{
valsAcross[i] += squares[i][j];
valsDown[j] += squares[j][i];
cout << "valsAcross[" << i << "] = " << valsAcross[i] << "\n";
cout << "valsDown[" << j << "] = " << valsDown[j] << "\n";
}
}
Incidentally, the code doesn't initialize the values in valsAcross,
valsDown, and valsDiag. That's probably the culprit.
--
Pete
Roundhouse Consulting, Ltd. (www.versatilecoding.com) Author of "The
Standard C++ Library Extensions: a Tutorial and Reference
(www.petebecker.com/tr1book)