Re: why does this work with Visual C++ 2005?
On 9/30/2013 7:45 PM, Lynn McGuire wrote:
Why does this work with Visual C++ 2005?
char buffer [10000];
void * test5 = & buffer;
I would think the compiler would give an error
on "& buffer", because "buffer" is the memory
address of the first element in the array, and
you can't get a memory address of a memory
address, there is no such thing.
The name of an array *decays* into a pointer to the first element of
that array in any expression *except* &<name>, where it's the address of
the entire array. Try wrapping a template around it to find out the
type of it.
> Note that
test5 and buffer do point to the same memory
address in the VC++ debugger after execution of
that line of code.
Yes, the address of the array is the same as the address of its first
element, the only thing is different is the *type* of that pointer.
Consider
char (*pb)[10000] = &buffer;
what's the type of 'pb'? Now, change the size either in the 'buffer'
declaration or here, do you get an error?
We do get a compiler error on:
char * test3 = & buffer;
And the following code compiles correctly:
char * test4 = & buffer [0];
The only thing i can think is the compiler
treats "& buffer" as "& buffer [0]" in the
void * case, assuming that is what the
programmer wanted.
Incorrect. See above.
V
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