Re: Junk

Garrett Hartshaw <>
Sat, 08 Jan 2011 00:22:38 -0500
Hash: SHA1

On 01/07/2011 11:19 PM, Paul wrote:

"Leigh Johnston" <> wrote in message

On 07/01/2011 20:57, Paul wrote:

"Leigh Johnston" <> wrote in message

On 07/01/2011 18:28, Paul wrote:

"Leigh Johnston" <> wrote in message

C++ is not an object oriented language; C++ is a multi-paradigm
language which includes support for object oriented programming.

The point is that C++ *supports* OOP.

Yes I already said that, why repeat it?

This means that C++ provides the mechanisms for OOP concepts like
encapsulation and virtual member functions.

I never said otherwise.

This means that to think of an object as a simple block of memory and
nothing else is incorrect as long as C++ supports OOP.

I already told you that objects can contain vtable pointers in one of

No I was the one who first suggested objects can contain a reference to
a function.

No you said that member functions are part of objects which that are
not; member functions are part of classes. A vtable pointer only
relates to virtual member functions and not all member functions are

the other bullshit threads you started; any vtable pointer or RTTI
pointer will be present in the object's storage region. An object is
simply a region of storage as far as C++ is concerned; you can deny
this all you want. "C++ object" is not the same as "OOP object".


The bullshit threads are fuelled by your bullshit argument that a member
function is not part of and object.

In C++ a member function is part of a class not part of an object;
this is a fact; everybody apart from you who has contributed to these
threads created by you concurs that this is a fact.

You can't just make statements to define the C++ language as you
interpret it. You state them as a fact with nothing to support it.
If *everyone* else agrees with you it doesn't mean you are correct.

its simple.....

Cat felix;
//The member function Meow() belongs to felix

Wrong; the member function Meow() is part of Cat not part of felix.

Please note the difference between felix.Meow() and simply Meow().
My comment implies felix.Meow() belongs to felix not simply Meow(),
which is what you have said to be wrong.
Whatever the calling mechanisms, there is a connection to suggest
felix.Meow() is bound to felix. And of course the obvious calling syntax
which also implies this.
felix.Meow() has no connection(see note) to class Cat and it's certainly
not physically inside the class.

Note: felix.Meow() is a function that has been invoked for the given
object felix. Please do not confuse this with the function declaration
in the Cat class

By your theory it cannot be 'part of' something unless it physically
exists within it.
felix.Meow() does not exist inside class Cat anymore than it exists
inside the object felix.

Also with:

There is only an object and a member function in this statement.
You state that this member function is a member of a class and not a
member of an object. But that is surely incorrect as there is no class
in this statement.
A class is not an object, so where does your class come from?

Cat oscar;
//oh look oscar also has a member function Meow()

Is oscars Meow the same as felix's meow? No because each Meow belongs to
a different cat.

You couldn't be any more wrong.

oscar.Meow() is a completely different function than felix.Meow().
They do not exist in the same process.

You provide no argument or evidence to suggest otherwise.

There is a concept of ownership between the object and the
If you cant understand this concept please say so and I will try to
explain further.
The fact that that the function is not actually stored within the
objects memory area is pretty irrellevant. Allthough I can see how a
person of low intelligence would be confused by this..


Is this a last resort to escape from the argument without:
a) admitting you were wrong.
b) risking the possibility of showing your true level of knowledge.
c) having to accept the fact that you are not in the majority, when it
comes to the wider programming community.

Just to clarify, would you say that in the following, meow( &oscar ) is
a different function than meow( &felix )?

class Cat;
void meow( Cat * );
Cat oscar;
Cat felix;

meow( &oscar );
meow( &felix );

If not, know that a member function is usually implemented as if the
object it is called on is passed as an implicit first parameter. For
example, the following does the same thing.

class Cat {
    void meow();

oscar.meow(); // oscar is passed as an implicit parameter
felix.meow(); // felix is passed as an implicit parameter

In fact, if they are implemented the same they will both do the same thing.

void meow( Cat * this ) {
    std::cout << this << std::endl; //print out the address of
                    //the cat

void Cat::meow() {
    std::cout << this << std::endl; //print out the address of
                    //the cat (passed implicitly)
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