Re: detecting integer overflow

From:
"Crosbie Fitch" <crosbie@digitalproductions.co.uk>
Newsgroups:
comp.lang.c++.moderated
Date:
27 Jun 2006 07:10:23 -0400
Message-ID:
<JdCdnc6pfsNWNgLZRVnyqQ@bt.com>
"Christopher Merrill" <cmerrill@sbcglobal.net> wrote in message
news:An_mg.122535$dW3.16869@newssvr21.news.prodigy.com...

Isn't there a way to generate an exception, which we can do with floating
point types?


Perhaps some implementations have exceptions for pointer arithmetic
overflow?
Scale your values up as appropriate, e.g.

void*p =(unsigned)a<<30;
p+=(unsigned)b<<30; // Exception on p overflow? (only good for additive)

How about bounds checking/buffer overrun that may be available on some
implementations?

char array[MAX_INT];
int a,b,c;
long r;
for (;;)
{ array[r=a*b]=0; // Exception on out of bounds?
     c=(int)r;
}

Probably easiest to do this:

//if calculation can be shown to overflow by inspecting arguments
     // inspect arguments
     if (will overflow)
         throw exception;

or

// if overflow can always be detected by result inspection
     // inspect result
      if (has overflown)
         throw exception;

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