Re: What is the output of this program?

From:
derek@antiquark.com
Newsgroups:
comp.lang.c++.moderated
Date:
8 Jul 2006 19:34:26 -0400
Message-ID:
<1152370695.731442.184170@h48g2000cwc.googlegroups.com>

A mistake made me stare at the screen for a while ...
Could you give some hints to avoid similar mistakes systematically?


Probably the easiest change would be to use the string's "at" function
for range-checked access, and encase your code in a try/catch block to
print an error message.

Also, you could use "vector<string>" instead of "string v1[5]". vector
also provides a at() function, but you usually have to initialize it
with a bunch of .push_back's.

Derek.

Your code would look like this. When executed, it will print a
string::at exception, indicating that you tried to access beyond the
end of a string.

=======
#include <string>
#include <iostream>

using namespace std;

string ToUpper(const string& s1)
{
        string s2;
        for (int i = 0; i < s1.size(); ++i)
                if (isalpha(s1.at(i))) s2.at(i) = toupper(s1.at(i));
        return s2;

}

int main()
{
    try
    {
      string v1[5] = {"This", "is", "a", "small", "quizz"};
      string v2[5];
      for (int i = 0; i < 5; ++i)
      {
          v2[i] = ToUpper(v1[i]);
       cout << v1[i] << " " << v2[i] << endl;
      }

   }
   catch(exception& x)
   {
     cout << "EXCEPTION: " << x.what() << endl;
   }
   return 0;
}
=========

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