Re: exception

From:

"Victor Bazarov" <v.Abazarov@comAcast.net>

Newsgroups:

comp.lang.c++

Date:

Mon, 24 Jul 2006 16:00:14 -0400

Message-ID:

<ea38si$u7o$1@news.datemas.de>

junw2000@gmail.com wrote:

In the following code:

#include <iostream>
#include <exception>
using std::string;
using std::exception;

class STACK {
public:
STACK(): size(0){
   str = new string[MAX];
}
void push(string s){
   try{
     if(size == MAX){
       throw 10;
     }
     str[size++] = s;
   }
   catch(int){
     std::cout<<"stack is full."<<std::endl;
     throw "A"; // LINE1
   }

}
string pop(){
   if(size == 0){
     std::cout<<"stack is empty"<<std::endl;
     return " ";
   }
   return str[--size];
}
bool empty(){
   return size == 0;
}

private:
enum { MAX = 3};
string *str;
int size;
};

int main(){
string ss;
STACK stack1;
stack1.push("hello");
stack1.push("you");
stack1.push("he");
stack1.push("it");

/* LINE2
catch(...){

OK, it's a 'catch' block. Where is the 'try' block for it?

std::cout<<"rethrow."<<std::endl;
}
*/
}

At LINE1, I re-throw an exception. How to catch it?
I tried to use the catch block at LINE2, but it cause error: syntax
error before `catch'

You need to add 'try' before it. Right now it's like an "else"
without the corresponding "if"...

V
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