Re: Exception Handling in Release Mode

From:
"Grizlyk" <grizlyk1@yandex.ru>
Newsgroups:
comp.lang.c++
Date:
Thu, 15 Feb 2007 18:22:05 +0300
Message-ID:
<er1trn$lu0$1@aioe.org>
Mohan wrote:

It is working fine in Win32 Debug build, but it is not catching the
exception in Win32Release mode.


1.
In the code

try
{
     int m = 17/i;
}


"m" is assigned, but never used, and in "Win32Release mode" can be optimized
and the try block can be removed. To always get the error, place the "int
m=0;" declaration into global scope.

2.
You can try to use signals and manual trap points, but it is not beauty
solution and not always work.

#include <signal.h>
int trap_point=0;

extern "C" void your_signal_handler(int)
{
    signal(SIGFPE,your_signal_handler);
    cout<<"SIGFPE catched"<< endl;

    //here system-depended can you continue after signal or not
    //CPU and OS mostly can, because they store
    //point of execution of synced hardware exception
    //but C++ library not always use the data correctly
}

int main(int argc, char* argv[])
{
int i = 0;


    signal(SIGFPE,your_signal_handler);

try
{


    enum {THE_POINT=1};
    trap_point=THE_POINT;

     int m = 17/i;


//Here SIGFPE can be catched and processed to continue execution
    if( !trap_point )throw THE_POINT;

}
catch(...)
{
     cout<<"Main - Catch"<<endl;
}
cout <<"End of Main" <<endl;

return 0;
}


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