Reducing the virtual function table size...

From:
"Chris Thomasson" <cristom@comcast.net>
Newsgroups:
comp.lang.c++
Date:
Mon, 16 Apr 2007 18:40:18 -0700
Message-ID:
<JaWdnRcjD4HduLnbnZ2dnUVZ_r2onZ2d@comcast.com>
Consider an an object that that can has 7 or 8 functions. If you create an
abstract base class for the "interface" of the object, well, that means 7 or
8 pure virtual functions right? Well, IMHO, that's way too much... I was
wondering if the following technique is "frowned" upon:

<pseudo-code>
_____________
typedef struct ... vztimespec_t;

class condmutex_base {
 public:
  enum wait_e {
    WAITLOCK, TRYLOCK, WAITCOND
  };

  enum wake_e {
    UNLOCK, SIGNAL, BROADCAST
  };

protected:
  condmutex_base() {}

public:
  virtual ~condmutex_base() {}

private:
  virtual bool wait(wait_e, vztimespec_t const*) = 0;
  virtual bool wake(wake_e) = 0;

public:
  inline void unlock() { wake(wake_e::UNLOCK); }
  inline void waitlock() { wait(wait_e::WAITLOCK, 0); }
  inline void waitcond() { wait(wait_e::WAITCOND, 0); }
  inline bool trylock() { return wait(wait_e::TRYLOCK, 0); }
  inline bool signal() { return wake(wake_e::SIGNAL); }
  inline bool broadcast() { return wake(wake_e::BROADCAST); }

  inline bool timedwaitcond(vztimespec_t const *tspec) {
    return wait(wait_e::WAITCOND, tspec);
  }
};
_____________

I only have 2 virtual functions now, not counting dtor, ect... Well, 2 is
better than 7, or 8?

Any thoughts?

:^)

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