Re: how to do this?
questions wrote:
I want to build a calculation,that is letting the first two integers
multiply,then printf the sum1,and next step I input the third
integer,I want to let the third integer multiply the sum1.I' ve done a
program,but it does not run as I want ,how could I rework it?
# include <stdio.h>
int main()
{int integer1;
int integer2;
int integer3;
int sum1;
int sum2;
printf("enter the first integer\n");
scanf("%d",&integer1);
printf("enter the second integer\n");
scanf("%d",&integer2);
sum1=integer1 * integer2;
printf ('sum1 is equal to %d\n",sum1);
scanf("%d",&sum1);
printf("enter the third integer\n");
scanf("%d",&integer3);
sum2=sum1*integer3;
printf("the sum2 is %d\n",sum2);
return 0;}
#include <cstdlib>
#include <iostream>
#include <stdexcept>
template<typename T>
T read(std::istream& in) {
T t;
if (in >> t) {
return t;
}
throw std::runtime_error( "bad input" );
}
template<typename T>
T prompt(std::string const& message) {
std::cout << message << '\n';
return read<T>(std::cin);
}
int main() try {
int const integer1 = prompt<int>("enter the first integer");
int const integer2 = prompt<int>("enter the second integer");
int const product1 = integer1 * integer2;
std::cout << "product1 is equal to " << product1 << '\n';
int const integer3 = prompt<int>("enter the third integer");
int const product2 = product1 * integer3;
std::cout << "product2 is equal to " << product2 << '\n';
return EXIT_SUCCESS;
} catch (std::exception const& exception) {
std::cerr << "error: " << exception.what() << '\n';
return EXIT_FAILURE;
}