Re: Preventing implicit calling of non-explicit constructor.

From:
Alan Johnson <awjcs@yahoo.com>
Newsgroups:
comp.lang.c++
Date:
Tue, 02 Dec 2008 19:58:04 -0800
Message-ID:
<gh504e$r4i$1@news.motzarella.org>
jason.cipriani@gmail.com wrote:

I have an application with a class "AppException" derived from
std::exception. I have full control over the implementation of
"AppException". I have two constructors like this:

class AppException {
public:
        ...
    AppException (const char *msg, ...);
    AppException (const std::exception &cause, const char *msg, ...);
        ...
};

The first constructor takes a printf format string and optional
parameters. The second takes an std::exception as the root cause, and
the same printf-style message. This functionality is critical (I need
to be able to construct an AppException from just a message, or from a
message and an std::exception root cause), although this particular
interface is not critical.

My problem is that std::exception has a non-explicit const char *
constructor. Therefore it can be implicitly converted from a const
char *. So in cases where I am using the no-cause constructor but
where my format parameters are a single additional string, e.g.:

   throw AppException("Some string: %s", someString);

The compiler (VS 2008's compiler) complains that both constructors are
possible matches (the second constructor also matches, it attempts to
implicitly convert the const char * to an std::exception, and pass
someString as "msg").

How can I get rid of this ambiguity, but still keep the same
functionality? I'm kind of frazzled and having trouble coming up with
ideas. If I could somehow say that I wanted std::exception(const char
*) to be explicit, that would be one way to solve the problem, but I
don't think that's possible.

Thanks,
Jason


std::exception doesn't have a constructor that takes a const char *.
It's full definition according to 18.6.1 is:

namespace std {
   class exception {
   public:
      exception() throw();
      exception(const exception&) throw();
      exception& operator=(const exception&) throw();
      virtual ??exception() throw();
      virtual const char* what() const throw();
   };
}

Seems like you've found an error in Microsoft's implementation.

Anyway, the workaround is to exploit the fact that only one implicit
conversion is allowed. Create a class to wrap a standard exception:

class ExceptionWrapper
{
public:
     ExceptionWrapper(const std::exception & e) : m_ref(e)
     {}

     const std::exception & get() const
     {
         return m_ref;
     }
private:
     const std::exception & m_ref;
};

Then change your exception class's interface to accept that:

class AppException {
public:
     ...
     AppException (const char *msg, ...);
     AppException (const ExceptionWrapper &cause, const char *msg, ...);
     ...
};

Within the AppException class use ExceptionWrapper::get to access the
exception.

You can still pass a std::exception as the first argument because an
ExceptionWrapper can be implicitly created, but because only one
implicit conversion is allowed, there is no way for the second
constructor to match a call with const char * as the first argument.

--
Alan Johnson

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