Re: Being Confused by /EH Exception Handling Model

From:

wuguangwen734@gmail.com

Newsgroups:

microsoft.public.vc.language

Date:

Sun, 7 Dec 2008 04:48:33 -0800 (PST)

Message-ID:

<5e28b671-3879-4972-8890-9c9aa9a4ad29@q26g2000prq.googlegroups.com>

I assume you refer to this page:
"Exception Specifications"http://msdn.microsoft.com/en-us/library/wfa0edys.aspx

There was no typing error.The article indeed says "extern C functions
never throw a C++ exception".
I refer to this page:
http://msdn.microsoft.com/en-us/library/1deeycx5.aspx
Why there are two version of MSDN? Don't you mean I've referenced the
wrong source of MSDN?

It happens because f4 throws (via f1) a C++ exception, not SEH
exception. When MSDN speaks about C functions throwing exceptions,
then SEH exception are assumed.

OK, based on this notion, I changed the example as follows:

// only valid if compiled without /EHc
// /EHc means assume extern "C" functions don't throw exceptions
   extern "C" void f4(void);
   void f4(void) {
    int i=0;
    int j= 5/i;
    //f1();
   }

   int main() {
    try {
        f4();
    }
    catch(...) {
        printf_s("Caught exception from f4\n");
    }
   }
And then compile it using the /EHc.As the comment says,"EHc means
assume extern "C" functions don't throw exceptions". But the outcome
is not the same as it predicts,for f4 does throw an exception caught
by catch(...). How to figure it out?