Re: Suggestion about formatting

From:
Michael DOUBEZ <michael.doubez@free.fr>
Newsgroups:
comp.lang.c++
Date:
Wed, 21 Jan 2009 10:47:49 +0100
Message-ID:
<4976ed32$0$750$426a74cc@news.free.fr>
Barzo wrote:

Hi,

in a my previous post (http://groups.google.it/group/comp.lang.c++/
browse_frm/thread/fcd414d039dbd6be#) I had to convert a buffer into a
timestamp string:

[1F][4D][BC][77][80] -> 20030630073000

Now I have to do the opposite: having a string 20030630073000 I have
to return a buffer [1F][4D][BC][77][80].


Perhaps the design solution would be to make a class that stores a
timestamp and as methods to read/write the different encoding. Rather
than coupling the two each time. It would make testing also easier.

The econding is like this:

00011111 01001101 10111100 01110111 10000000 -> 1F 4D BC 77 80
| 2003 | 06 | 30 | 07 | 30 | 00 |

where the year use 14 bits, months 4, days 5 and so on..

I have tought to do something like this:

int encode_time(const std::string& value, std::string& ret_val)
{
  std::stringstream ss;
  int i;
  double d;
  int st;

  //value has to be YYYYMMDDhhmmss

  ss << value.substr(0, 4);
  if( (ss >> i).fail() ) { st = ss.rdstate(); return st;}
  d = i * 0x4000000;


Beware of endianess. And double is not guaranteed to represent you number.

  ss.flush();
  ss << value.substr(4, 2);
  if( (ss >> i).fail() ) { st = ss.rdstate(); return st;}
  d += i * 0x400000;
  ss.flush();
  ss << value.substr(6, 2);
  if( (ss >> i).fail() ) { st = ss.rdstate(); return st;}
  d += i * 0x20000;
  ss.flush();
  .....
  .....
  ss.flush();
  ss << d;
  ret_val = ss.str();

}


Maybe you can consider using boost.lexical_cast (or roll your own
lexical_cast which is not that hard).

You function would be rewritten
try{
const unsigned year =lexical_cast<unsigned>(value.substr(0,4));
const unsigned month=lexical_cast<unsigned>(value.substr(4,2));
const unsigned day =lexical_cast<unsigned>(value.substr(6,2));
....
//re-encode
}
catch(const bad_lexical_cast& e)
{
   //conversion error
}

The first conversion (0, 4) is ok and i 03, but the second one (4,2)
fails and the func returns 7.
Where I wrong?

flush() doesn't remove the content of the underlying buffer in only
ensures the synchronization with underlying buffer.

You can Set your stringstream with:
ss.str(value.substr(4,2));
And use it rather than ss<<value...

--
Michael

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