Re: when delete do not call destructor

From:
S S <sarvesh.singh@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Thu, 5 Mar 2009 08:46:44 -0800 (PST)
Message-ID:
<b1ca3296-4870-4b6c-b311-ebd4260e10e2@i20g2000prf.googlegroups.com>
On Mar 5, 9:38 pm, blargg....@gishpuppy.com (blargg) wrote:

SG wrote:

On 5 Mrz., 16:06, S S <sarvesh.si...@gmail.com> wrote:

I can not write full code as it is 20000 lines kind of copywrite
thing.


Nobody would like to see those 20000 lines anyways. Victor said
"Please post
real code.". He wanted to see a small program that is compilable or
at least supposed to compile.

class A{
public:
void *operator new(size_t, void *p) {return(p);}

void *operator new(size_t n) throw(std::bad_alloc)
{ My_allocation_routine(&someInternalVar, n);}

void operator delete(void* p, size_t n) {My_deallocation_routine(p,
n);}
..
..
~A() {}

};


This is not "real code". It lacks #include directives, contains ".."
which doesn't parse, and misses a definition of My_allocation_routine.


What, your C++ compiler doesn't support the new C++0x ".." directive,
which has it read the mind of the poster and fill in the blanks?

Seriously, to post "real code" would require spending some "real time"
(about 3 minutes) putting together a stand-alone code sample that
demonstrates the problem. The time spent putting that together might even
lead to a solution without having to post anything here.

I will offer one bit of help: debuggers often have limitations about what
can be stopped at. Best way to find out if that's the cause of the missed
breakpoint is to write a separate code example to see if that's the case.
As usual, remove everything that doesn't make the problem go away. My
guess is that your debugger can't breakpoint on inline functions, at leas=

t

not without some special compiler option.


The same code is working for all other objects, and with small piece
of code I am not able to replicate it. It's kind of weird issue and I
don't know why destructor is not called when delete is asked.

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