Re: template copy constructor

I have tried the code below with std::auto_ptr

std::auto_ptr<int> api;

api = f<int>();

and I have gotten the error

------ Build started: Project: auto_ptr_build, Configuration: Debug
Win32 ------

Compiling...

auto_ptr_build.cpp

c:\documents and settings\vgrigoryev\my documents\visual studio
2005\projects\auto_ptr_build\auto_ptr_build.cpp(117) : error C2679: binary
'=' : no operator found which takes a right-hand operand of type
'odd_ptr<T>' (or there is no acceptable conversion)

with

[

T=int

]

c:\program files\microsoft visual studio 8\vc\include\memory(587): could be
'std::auto_ptr<_Ty> &std::auto_ptr<_Ty>::operator =(std::auto_ptr<_Ty> &)
throw()'

with

[

_Ty=int

]

c:\program files\microsoft visual studio 8\vc\include\memory(593): or
'std::auto_ptr<_Ty> &std::auto_ptr<_Ty>::operator =(std::auto_ptr_ref<_Ty>)
throw()'

with

[

_Ty=int

]

while trying to match the argument list '(std::auto_ptr<_Ty>, odd_ptr<T>)'

with

[

_Ty=int

]

and

[

T=int

]

Build log was saved at "file://c:\Documents and Settings\vgrigoryev\My
Documents\Visual Studio 2005\Projects\auto_ptr_build\Debug\BuildLog.htm"

auto_ptr_build - 1 error(s), 0 warning(s)

========== Build: 0 succeeded, 1 failed, 0 up-to-date, 0 skipped ==========

Does it mean that inside the standard auto_ptr there is no such operator as
I used??

odd_ptr & operator=( odd_ptr_ref<T> rhs ) throw()

{

reset( rhs.r.release() );

return ( *this );

}

Vladimir Grigoriev