Re: Will a constructor be able to "call" a constructor in C++0x?

From:
Pavel <pauldontspamtolk@removeyourself.dontspam.yahoo>
Newsgroups:
comp.lang.c++
Date:
Sun, 22 Aug 2010 21:22:45 -0400
Message-ID:
<4c71cd64$0$17896$c3e8da3@news.astraweb.com>
Howard Hinnant wrote:

On Aug 22, 4:26 am, "Bo Persson"<b...@gmb.dk> wrote:

joe wrote:

The subject is the question. Furthering, doesn't it make sense to
consolidate code in a "main" constructor and have other ones use it
to provide different instantiation ways for a class? (rhetorical, I
think, because I think so). It's all about providing a rich class
instantiation interface to users (programmers) while having
maintainable and reliable source code, and allowing one constructor
to "call" another (quotes used because I just want the capability
and am not too worried about the syntax) gives exactly that.


Yes, it is called a "delegating constructor" when one constructor has
another constructor of the same class in its initializer list.

struct C
{
    C( int ) { } // #1: non-delegating constructor
    C(): C(42) { } // #2: delegates to #1

};


Imho, this is one of the more exciting features in C++0X, and not just
because it allows you to consolidate initialization code. I like it
for its ability to make writing exception safe code so much easier.

For example consider a class C which holds two resources (I'll just
use int pointers for ease of demonstration). Such a class in C++03
might be coded like this:

class C
{
     int* data1_;
     int* data2_;

public:
     C() : data1_(0), data2_(0) {}

     C(int i, int j)
         : data1_(0), data2_(0) {}
     {
         try
         {
             data1_ = new int(i);
             data2_ = new int(j);
         }
         catch (...)
         {
             delete data1_;
             throw;
         }
     }

     C(const C& c)
         : data1_(0), data2_(0) {}
     {
         try
         {
             if (c.data1_)
                 data1_ = new int(*c.data1_);
             if (c.data2_)
                 data2_ = new int(*c.data2_);
         }
         catch (...)
         {
             delete data1_;
             throw;
         }
     }

     ~C()
     {
         delete data1_;
         delete data2_;
     }
}

Note the need to wrap the non-default constructors up with try-catch-
rethrow.

Delegating constructors have the property that once /any/ constructor
completes, the class is considered constructed, and thus its
destructor must run when the class goes out of scope. This means that
now the non-default constructors can rely on the default constructor
to construct the class, and after that, they can count on the
destructor to run if they throw an exception:

class C
{
     int* data1_;
     int* data2_;

public:
     C() : data1_(nullptr), data2_(nullptr) {}

     C(int i, int j)
         : C()
     {
         data1_ = new int(i);
         data2_ = new int(j);
     }

     C(const C& c)
         : C()
     {
         if (c.data1_)
             data1_ = new int(*c.data1_);
         if (c.data2_)
             data2_ = new int(*c.data2_);
     }

     ~C()
     {
         delete data1_;
         delete data2_;
     }
}

Delegating constructors just really cleans up the code to deal with
exception safety, at least for those types that can delegate to a
resource-less constructor! :-)

-Howard

This is certainly a useful technique that delegating constructors make
possible, but, just for the record: as usual there is no entirely free
cheese: the cost is that a member variable is written to more than once.

-Pavel

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