Re: C++ rule on function-try-block

From:
=?UTF-8?B?6JCMIOacsQ==?= <rigaje@gmail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Thu, 11 Nov 2010 06:54:32 CST
Message-ID:
<cbe3cea5-a9aa-4a15-bad1-11dbb0ee91c8@c39g2000yqi.googlegroups.com>
On Nov 10, 12:30 pm, muler <mulugeta.abe...@gmail.com> wrote:

Hi all,

[ISO/IEC 14882:1998] A function-try-block associates a handler-seq
with the ctor-initializer, if present, and the function-body. An
exception thrown during the execution of the initializer expressions
in the ctor-initializer **or during the execution of the function-body
transfers control to a handler in a function-try-block in the same way
as an exception thrown during the execution of a try-block transfers
control to other handlers.**

To demonstrate the statement in between **...**, I cooked up the
following example (using VC++2010):

Given:
=====

class GenericError {};
void Print(int x)
{
        if (x < 0) throw GenericError();

}

class X {
public:
        X();

};

Case 1: // no error executing this
=====
X::X()
{
        try
        {
                Print(-1);
        }
        catch(const GenericError& ge)
        {
        }

}

Case 2: // error while trying to execute this
======

X::X() try
{
        Print(-1);}

catch(const GenericError& ge)
{

}

According to the standard, the behavior for Case 1 and Case 2 should
be the same, right? But it is not in VC++2010. Is this a compiler
issue or what?

Thanks,
Muler


According to my understanding of the standard, your two cases fall
into 15.3.16,
"The exception being handled is rethrown if control reaches the end of
a handler of the function-try-block of a constructor or destructor.
Otherwise, a function returns when control reaches the end of a
handler for the function-try-block (6.6.3). Flowing off the end of a
function-try-block is equivalent to a return with no value; this
results in undefined behavior in a value-returning function (6.6.3)."

So in your second case, the exception is thrown and handled and then
rethrown

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