Re: exception

From:
"Victor Bazarov" <v.Abazarov@comAcast.net>
Newsgroups:
comp.lang.c++
Date:
Mon, 24 Jul 2006 16:00:14 -0400
Message-ID:
<ea38si$u7o$1@news.datemas.de>
junw2000@gmail.com wrote:

In the following code:

#include <iostream>
#include <exception>
using std::string;
using std::exception;

class STACK {
public:
 STACK(): size(0){
   str = new string[MAX];
 }
 void push(string s){
   try{
     if(size == MAX){
       throw 10;
     }
     str[size++] = s;
   }
   catch(int){
     std::cout<<"stack is full."<<std::endl;
     throw "A"; // LINE1
   }

 }
 string pop(){
   if(size == 0){
     std::cout<<"stack is empty"<<std::endl;
     return " ";
   }
   return str[--size];
 }
 bool empty(){
   return size == 0;
 }

private:
 enum { MAX = 3};
 string *str;
 int size;
};

int main(){
 string ss;
 STACK stack1;
 stack1.push("hello");
 stack1.push("you");
 stack1.push("he");
 stack1.push("it");

/* LINE2
 catch(...){


OK, it's a 'catch' block. Where is the 'try' block for it?

   std::cout<<"rethrow."<<std::endl;
 }
*/
}

At LINE1, I re-throw an exception. How to catch it?
I tried to use the catch block at LINE2, but it cause error: syntax
error before `catch'


You need to add 'try' before it. Right now it's like an "else"
without the corresponding "if"...

V
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