Re: private construction on GCC

From:
Mark P <usenet@fall2005REMOVE.fastmailCAPS.fm>
Newsgroups:
comp.lang.c++
Date:
Mon, 24 Jul 2006 23:35:08 GMT
Message-ID:
<MOcxg.137643$H71.91141@newssvr13.news.prodigy.com>
Kai-Uwe Bux wrote:

brianhray@gmail.com wrote:

I get an access exception on Release() on GCC but worked on different
compiler,


Ok, sounds like undefined behavior.

I am trying to figure out if there is anything with this code
in a header:

class CountObject {
private:
long count;
public:
CountObject() : count(0) {}
CountObject(const CountObject&) : count(0) {}
virtual ~CountObject() {}
CountObject& operator=(const CountObject &) { return *this; }

void Grab() { count++; }
void Release() {
           if (count > 0) count--; //< Exception Here
           if (count <= 0) {
              delete this;
            }
}

// attribute functions
long Count() const { return count; }
};

Any insight would be helpful. What is the best way (most standard) to
prevent this problem.


The code you posted, does not show any problems. However, calling

  delete this;

can be tricky. If I was to take a wild guess, I would conjecture that in
your other code, you call Release() (or some other member function) on an
object that has already self-detonated. In that case, you enter UB.

Another catch with "delete this" is that is presupposes the object has been
created via new(). Maybe you call Release() on an object on the stack
causing UB that way.


That would be my first guess too. To the OP, if you're going to allow
the object to delete itself then it's a good idea to enforce that all
instances are dynamically allocated. One such approach is explained in
the FAQ:

http://www.parashift.com/c++-faq-lite/freestore-mgmt.html#faq-16.21

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