Re: Exception safety: how to assign std::string when strong guarantee is needed?

From:
Alberto Ganesh Barbati <AlbertoBarbati@libero.it>
Newsgroups:
comp.lang.c++.moderated
Date:
Thu, 26 Jul 2007 16:38:40 CST
Message-ID:
<Nh7qi.74946$%k.215593@twister2.libero.it>
jpalecek@web.de ha scritto:

On Jul 25, 8:40 pm, Alberto Ganesh Barbati <AlbertoBarb...@libero.it>
wrote:

Niels Dekker - no return address ha scritto:

How would you assign one std::string to another, when you need to have
the "strong guarantee", with respect to exception safety?
It seems to me that the following five attempts only offer the basic
guarantee:
void Foo( const std::string & string1, std::string & string2 ) {
  // Attempt 1. operator=
  string2 = string1;
  // Attempt 2. Copy-and-swap.
  std::string(string1).swap(string2);
  // Attempt 3. Copy-and-swap (non-member).
  std::string temp(string1);
  swap(string2, temp);
  // Attempt 4. assign.
  string2.assign(string1);
  // Attempt 5. assign iterator-range.
  string2.assign(string1.begin(), string1.end());
}

Pardon my ignorance, but I don't see why you are saying that case 2 and
3 are not providing the strong guarantee. Could you please elaborate?


See: http://www.research.att.com/~bs/3rd_safe0.html


This paper seems to support my intuition: if I read it correctly, it
claims that case 2 and 3 provide the strong guarantee (see E.5.1).

The problem is it isn't quite explicitly written in the standard, but
it should hold that swap has nothrow guarantee. However, your
case 2 is not an asignment.


Case 2 actually performs an assignment. Its form may look exotic at
first, but it is essentially identical to case 3: string1 is copied to a
temporary object and the temporary object is swapped with string2.

HTH,

Ganesh

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