Re: Exception safety: how to assign std::string when strong guarantee is needed?
jpalecek@web.de ha scritto:
On Jul 25, 8:40 pm, Alberto Ganesh Barbati <AlbertoBarb...@libero.it>
wrote:
Niels Dekker - no return address ha scritto:
How would you assign one std::string to another, when you need to have
the "strong guarantee", with respect to exception safety?
It seems to me that the following five attempts only offer the basic
guarantee:
void Foo( const std::string & string1, std::string & string2 ) {
// Attempt 1. operator=
string2 = string1;
// Attempt 2. Copy-and-swap.
std::string(string1).swap(string2);
// Attempt 3. Copy-and-swap (non-member).
std::string temp(string1);
swap(string2, temp);
// Attempt 4. assign.
string2.assign(string1);
// Attempt 5. assign iterator-range.
string2.assign(string1.begin(), string1.end());
}
Pardon my ignorance, but I don't see why you are saying that case 2 and
3 are not providing the strong guarantee. Could you please elaborate?
See: http://www.research.att.com/~bs/3rd_safe0.html
This paper seems to support my intuition: if I read it correctly, it
claims that case 2 and 3 provide the strong guarantee (see E.5.1).
The problem is it isn't quite explicitly written in the standard, but
it should hold that swap has nothrow guarantee. However, your
case 2 is not an asignment.
Case 2 actually performs an assignment. Its form may look exotic at
first, but it is essentially identical to case 3: string1 is copied to a
temporary object and the temporary object is swapped with string2.
HTH,
Ganesh
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