Re: Howto rethrow an exception outside a catch block?

From:
"Alf P. Steinbach" <alfps@start.no>
Newsgroups:
comp.lang.c++
Date:
Wed, 08 Aug 2007 15:51:36 +0200
Message-ID:
<13bjin75d5fcfe0@corp.supernews.com>
* reuce-google@yahoo.de:

Hi folks,

I want to store an exception and rethrow it later:

CException m_pEc = NULL; // Class variable.

try
{
    throw new CMemoryException();
}
catch (CException * pEc) // Catch all exceptions derived from
CException.
{
    m_pEc = pEc; // Store Exception.
}

....

CMemoryException is derived from CException. But if I now throw m_pEc
the Exception raised will be caught merely by CException catch blocks,
unfortunately:

try
{
    CException * pEc = m_pEc;
    m_pEc = NULL; // Clear variable.
    throw pEc;
}
catch (CMemoryException * pEc)
{
    // Won't catch the exception.
}
catch (CException * pEc)
{
    // Will catch the exception.
}

....

How can I rethrow the exception, so that it will be thrown with the
right type information (CMemoryException) - even if I don't know the
type beforehand?


In the catch block you can do

   throw;

Note that it's not a good idea to throw pointers to dynamically
allocated memory, for it may be caught by a catch(...), and who's then
to deallocate?

Better use standard C++ exceptions.

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