Re: Exception specification and reference types

From:
Greg Herlihy <greghe@mac.com>
Newsgroups:
comp.std.c++
Date:
Mon, 19 Nov 2007 17:54:17 CST
Message-ID:
<c13c46de-b334-456c-b763-9f9e0f343487@e10g2000prf.googlegroups.com>
On Nov 16, 9:14 am, andreytarasev...@hotmail.com (Andrey Tarasevich)
wrote:

   struct A {
     struct AA {};
     virtual void foo() throw(AA&);
   };

   struct B : A {
     struct BB : AA {};
     virtual void foo() throw(AA&, BB&);
   };

According to my understanding, using reference types in the exception
specification should be basically equivalent to using corresponding
non-reference types. Also, when it comes to determining whether the
specification of a virtual function is extended in the derived class, reference
types could be thought of as corresponding pointer types.


But a reference type is not a pointer type - so the rules that apply
to pointer types do not automatically extend to reference types.

However, Comeau online refuses to compile the second example, complaining that
'B::foo's exception specification is more loose than that of 'A::foo'.


There are basically three types of exception specifications (involving
base and derived classes) to consider. And the question in each case
is whether a base claas exception specification "matches" a thrown
exception of a derived type. (if it does, then adding the derived type
to the exception specification would be legal - since the derived
type was already a match).

So, the three questions are:

   1. Does an AA exception specification match a BB type exception?
   2. Does " AA* " " " " BB* " " ?
   3. Does " AA& " " " " BB& " " ?

The answers are:

   #1. Yes - by the second bullet point in ?15.3/3 : AA is an
unambiguous base class of BB.
   #2 Yes - by the third bullet point: BB* converts to AA* implicitly
   #3. No. The first two bullets do not applyy because AA& is neither
the same type as - nor a base class of - BB& (just as AA* is not a
base class of BB*). And since neither type is a pointer type, the
third bullet point does not apply either - and there are no other
bullet points left by which an AA& exception specification would match
a BB& exception object.

Note that this conclusion does not mean that an AA& exception
specification prohibits BB& exceptions from being thrown. Because an
instance of a derived class is also an instance of its base class, a
BB& object may be thrown from a function with an AA& exception
specification - even if the AA& exception specification does not
"match" a BB& exception object.

Greg

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