Re: try-catch usage

From:
Pete Becker <pete@versatilecoding.com>
Newsgroups:
comp.lang.c++
Date:
Tue, 26 Aug 2008 13:04:10 -0400
Message-ID:
<2008082613041016807-pete@versatilecodingcom>
On 2008-08-26 12:44:48 -0400, Christian Hackl <hacki@sbox.tugraz.at> said:

red floyd wrote:

Per 15.1/8, "If no exception is presently being handled, executing a /
throw-expression/ with no operand calls terminate()."

In other words, a "throw;" must occur inside a catch block, or you
will be terminated.


I think that's too narrow. An exception can be handled even if you are
not currently inside of a catch block, can't it?


It depends on just what you mean by "inside" a catch block. Most people
would say that the throw; below is inside a catch block. If you call
handleException directly from main, i.e. not inside any catch block,
the program will, indeed, be terminated.

#include <exception>
#include <stdexcept>
#include <iostream>

void handleException()
{
   try
   {
     throw;
   }
   catch (std::exception const &exc)
   {
     std::cout << exc.what() << "\n";
   }
   catch (...)
   {
     std::cout << "unknown exception\n";
   }
}

int main()
{
   try
   {
     throw std::runtime_error("test");
   }
   catch (...)
   {
     handleException();
   }
}

Isn't this a perfectly standard-conforming program? It does not call
terminate() when compiled and run with VC or GCC.


--
  Pete
Roundhouse Consulting, Ltd. (www.versatilecoding.com) Author of "The
Standard C++ Library Extensions: a Tutorial and Reference
(www.petebecker.com/tr1book)

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