Re: what is the following type

From:
James Kanze <james.kanze@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Tue, 2 Dec 2008 05:02:34 -0800 (PST)
Message-ID:
<02be4db6-5bbe-4384-b313-b1c0cccd52fb@a12g2000yqm.googlegroups.com>
On Dec 1, 9:55 pm, Mosfet <mos...@anonymous.org> wrote:

I am looking at some source code and in one file there is the following
definition :


It looks more like C than C++. The naming conventions are also
illegal, resulting in a lot of undefined behavior (both in C and
in C++). However...

typedef enum _EXCEPTION_DISPOSITION {
     ExceptionContinueExecution,
     ExceptionContinueSearch,
     ExceptionNestedException,
     ExceptionCollidedUnwind,
     ExceptionExecuteHandler
} EXCEPTION_DISPOSITION;

typedef EXCEPTION_DISPOSITION EXCEPTION_ROUTINE (
     struct _EXCEPTION_RECORD *ExceptionRecord,
     void *EstablisherFrame,
     struct _CONTEXT *ContextRecord,
     struct _DISPATCHER_CONTEXT *DispatcherContext
     );
typedef EXCEPTION_ROUTINE *PEXCEPTION_ROUTINE;

EXCEPTION_ROUTINE __C_specific_handler;

I am puzzled by the EXCEPTION_ROUTINE definition, it looks
like a function pointer but without the *. Is it a function
pointer ?


No. It's a function (type). You can use it to declare
functions, but not to define them. Thus, __C_specific_handler
is an (extern) function, or it would be if the name didn't
trigger undefined behavior.

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