Re: Question on operator << overloading

From:
"Alf P. Steinbach" <alfps@start.no>
Newsgroups:
comp.lang.c++
Date:
Mon, 04 May 2009 18:58:47 +0200
Message-ID:
<gtn6oh$1ln$1@news.motzarella.org>
* shuisheng:

I have a question on operator << overloading on a class in a
namespace. For example:

#include <iostream>

namespace Geometry
{
  class Point
  {
    friend std::ostream& operator << (std::ostream& out, const Point&
pt);

  private:
    double x, y, z;
  };
};

inline std::ostream& operator << (std::ostream& out, const Point& pt)
{
  out << pt.x << pt.y << pt.z;
  return out
}

I got compilation errors: can not access class Point 's private
members x, y, and z. If I move the overloading function into the
Geometry namespace, it is fine. But I want to keep the function
global and do not want to make x, y, z public, how can I do for it?


<code file="A.cpp">
#include <iostream>

namespace Geometry {
     class Point;
}

inline std::ostream& operator<<(
     std::ostream& out,
     Geometry::Point const& pt
     );

namespace Geometry {
     class Point
     {
         friend std::ostream& ::operator<<(
             std::ostream& out,
             Geometry::Point const& pt
             );

     private:
         double x, y, z;
     };
}

inline std::ostream& operator<<(
     std::ostream& out,
     Geometry::Point const& pt
     )
{
     return out << pt.x << " " << pt.y << " " << pt.z;
}
</code>

<code file="B.cpp">
#include <iostream>

namespace Geometry {
     class Point
     {
     public:
         std::ostream& writeOn( std::ostream& out ) const
         {
             return out << x << " " << y << " " << z;
         }

     private:
         double x, y, z;
     };
}

inline std::ostream& operator<<(
     std::ostream& out,
     Geometry::Point const& pt
     )
{
     return pt.writeOn( out );
}
</code>

Cheers & hth.,

- Alf

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