Re: Knowing the implementation, are all undefined behaviours become implementation-defined behaviours?

From:
"Bo Persson" <bop@gmb.dk>
Newsgroups:
comp.lang.c,comp.lang.c++
Date:
Sun, 14 Feb 2010 11:24:48 +0100
Message-ID:
<7tq1amFn95U1@mid.individual.net>
Robert Fendt wrote:

And thus spake Seebs <usenet-nospam@seebs.net>
14 Feb 2010 07:03:57 GMT:

dereference a null pointer. (For instance, loops which check
whether a pointer is null may have the test removed because, if it
were null, it would have invoked undefined behavior to dereference
it...)


Sorry to interrupt, but since when is checking a pointer value
for 0 the same as deferencing it? Checking a pointer treats the
pointer itself as a value, and comparison against 0 is one of
the few things that are _guaranteed_ to work with a pointer
value. So if GCC really would remove a check of the form

if(!pointer)
 do_something(*pointer);

or even

if(pointer == 0)
 throw NullPointerException;

then GCC would be very much in violation of the standard. And
produce absolutely useless code, as well. What's the point of
having pointers in a language if you wouldn't even be able to
perform basic operations on them?


Yes, but there are cases where the compiler can determine that the
pointer is ALWAYS null or not-null, and remove code that would execute
otherwise. For example:

*pointer = 42;
if(pointer == 0)
   throw NullPointerException;

is known never to throw the exception!

Bo Persson

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