Re: how to implement a simple class forname?
Victor Bazarov wrote:
If I may... This sounds OK, only to take address of a member function
you need the class before the name:
map["method1"] = &OneClass::method1;
map["method2"] = &TwoClass::method2;
And when you call it, you can't prepend it with 'factory::'. You just
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Of course, you may.
well. I think that this is not neccesary because in the end the methods
will be of the same class.
i make this:
typedef void (*PtrMethod)(std::vector<std::string>);
map<const char*, PtrMethod*, ltstr> theMap;
Object * method1(std::vector<std::string>);
Object * method2(std::vector<std::string>);
map["method1"] = &method1;
map["method2"] = &method2;
Object * Factory::getObject(string label,vector<string> paramaters)
PtrMethod method = theMap[label];
Object * object = (*method)(parameters);
is it correct? what do you think?
thank you very much by your attention
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