Re: how to implement a simple class forname?
Victor Bazarov wrote:
well. I think that this is not neccesary because in the end the
methods will be of the same class.
i make this:
typedef void (*PtrMethod)(std::vector<std::string>);
map<const char*, PtrMethod*, ltstr> theMap;
Object * method1(std::vector<std::string>);
Object * method2(std::vector<std::string>);
map["method1"] = &method1;
map["method2"] = &method2;
Object * Factory::getObject(string label,vector<string> paramaters)
PtrMethod method = theMap[label];
Object * object = (*method)(parameters);
is it correct? what do you think?
Close, but incorrect. If your 'method1' and 'method2' return Object*,
you cannot declare 'PtrMethod' as returning "void". You have to make
sure the type is the same as the functions. That's the glaring error.
Then 'Factory::getObject' returns 'energia' where it should probably
Not so important ones include passing by value where passing by const
reference should be sufficient.
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Oh, you are rigth. I had an error: "PtrMethod" return "Object *" and
"Factory::getObject" returns a Object*. I'm mistaken when copying the
and too, you are rigth with passing by value or by const reference. I
will do it thus
Thank you very much for your help.
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