Re: Please Help Newbie with validation problem

"osmium" <>
Sun, 11 Feb 2007 06:26:08 -0800
"Morgan" writes:

I've been working on this code for about 2 days now, and can't get it
to work. Ultimately I need a algorithm to loop between my pieces of
validation code so that a variable meets 3 different conditions.

What I have is three while loops, example:

cout << "Please enter the number of judges: ";

The reason that there are two variables for the number of judges,
is because I need to find out if the user entered a floating point
value. You shouldn't have 3.5 judges, as the for loop which counts
the scores later on will never be able to reach the end condition.
What is happening is that I get floating point value of the number
of judges (num_judges_float). If the user entered an integer eg: 4,
and if you put that value into an integer variable (num_judges_int),
you just get 4. So if you minus the floating point value of judges
from the number of judges in the integer variable, you should yield
zero. Anything else means the user did not enter a integer so a while
loop traps the error.

cin >> num_judges_float;
num_judges_int = num_judges_float;

       while((num_judges_float - num_judges_int) > 0)
       cout << "\nError: You entered the number of judges with a
decimal point.\n\n";
       cout << "Please enter the number of judges with no decimal
point: ";

       cin >> num_judges_float;
       num_judges_int = num_judges_float;

// The header() function is called whenever input is given by the
// user. This produces the affect of keeping the text banner at the
// top of the console window the whole time.


       while(num_judges_int < 1)
       // can't have negative judges or zero judges!

       cout << "Error: The number of judges cannot be negative or
zero : ";
       cout << "\n\nPlease reenter the number of judges : ";
       cin >> num_judges_int;

       while(num_judges_int < 3)
   We aren't able to compute an average in the case that the number
          of judges is 1 or 2. This is because later in this program
we have
          to take the highest and lowest scores from the total of
          If we do this we have to divide the remaining total by the
          of judges minus two to get an average.(two for the two
scores we're
   getting rid of). In the case we have two judges, we would wind up
   dividing the total into zero (impossible) or in the case that we
   had only one judge, we would be dividing the total into a
   number which would then give a negative result. As these events
   don't lead to an average, it seemed best to me to give the user
   an error message to explain what was wrong.

       cout << "Sorry, this program cannot give an average if there
is less than three judges";
       cout << "\n\nPlease reenter the number of judges : ";
       cin >> num_judges_int;

I suggest rewriting so you have a function that gets one satisfactory number
and returns it. Call this function three times from main. A satisfactory
number is a positive integer, but you have divided the responsibility into
two parts and the input must meet both criteria. Since the while loops are
disjoint in your code, problems seem likely.

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