Re: Object that transfers ownership on assignment/copy
Scott Gifford wrote:
As a possible solution to a problem I'm trying to solve with an
iterator (see an earlier post by me with subject "Iterator
implementation questions: copy constructor and postfix increment"),
I'm trying to implement an object that transfers ownership on
assignment or copy, just like auto_ptr does.
With an auto_ptr, I can do this:
#include <string>
#include <memory>
#include <iostream>
using namespace std;
auto_ptr<string> ap_factory() {
return auto_ptr<string>(new string("foo"));
}
int main() {
auto_ptr<string> s = ap_factory();
auto_ptr<string> s2 = s;
cout << "s1=" << s.get() << ", s2=" << *s2 << endl;
}
and when "s2 = s" executes, the pointer that was held by "s" is
trasferred to "s2", and then the pointer in "s" is set to NULL. So, I
see this output:
s1=0, s2=foo
When I try to implement the same behavior in my own class, I have
compilation problems. Here's my small test case:
#include <string>
#include <iostream>
using namespace std;
class C {
public:
C(string *_s) : s(_s) { }
C(C &that) : s(that.s) { }
C& operator=(C &that) {
if (&that != this) {
s = that.s;
}
return *this;
}
const string *get() {
return s.get();
}
private:
auto_ptr<string> s;
};
C c_factory() {
return C(new string("foo"));
}
int main() {
C myC = c_factory();
Here you have a temporary from which you're trying to construct
an object. That operation requires binding a non-const reference
to the temporary, which is prohibited.
Take a look at how 'auto_ptr' is implemented and follow that instead
of trying to wrap it up.
C myC2 = myC;
cout << "myC=" << myC.get() << ", myC2 = " << *(myC2.get()) <<
endl;
return 0;
}
[..]
V
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