Re: template problem: local variable as non-type argument
On Feb 5, 6:05 am, potapo...@gmail.com wrote:
Option 1, "switch" statement is much faster than "if" one:
Base& Factory::createInstance(int i) {
switch(i){
case 1: return C<1>();
case 2: return C<2>();
...
}
}
Option 2, linear recursive helper function:
const int max_n = 100;
template<int n>
struct helper
{
static Base& func(int i)
{
return i == n? C<n>() : helper<n+1>::func(i);
}
};
template<>
struct helper<max_n>
{
static Base& func(int i)
{
return C<max_n>();
}
};
Base& Factory::createInstance(int i) {
return helper<0>(i);
}
<snip>
Base& func0()
{
return C<0>();
}
Base& func1()
{
return C<1>();
}
Base& func2()
{
return C<2>();}
...
Base& Factory::createInstance(int i) {
const Base& (*ptrs)()[]={func0,func1,func2,... /* can be filled by
Boost.Preprocessor too */};
return ptrs[i]();
}
Unfortunately all of those examples fail as they are returning
references to locals that go out of scope.
An appropriate fix for all of them, including the helper version which
I quite like, is to make a local static object like this:
Base & func0()
{
static const C<0> item;
return item;
}
BTW this pattern is very useful in cases where you benchmarked your
code and absolutely need the optimization of template specializations
to factor out variable coefficients into constants.
--jeffk++
www.jdkoftinoff.com
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