Re: Perl style hash
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none writes:
Sam wrote:
No need to overload anything. Both the key or the value in a std::map
can be any class, with the only restriction that the key class must
implement operator<() (ignoring the hair-splitting requirement for the
implementation of copy constructors and assignment operators).
Sure, but the type of the elements are determined at compile time. In
other words, you can't just do this:
std::map<std::string, Anything> x;
You surely can. It's just a matter of implementing "Anything".
x["a float"] = 5.0f;
x["an int"] = 10;
x["a string"] = "some text";
So? This calls for an overloaded Anything::operator=():
class Anything {
public:
// ..
Anything &operator=(double);
Anything &operator=(int);
Anything &operator=(std::string);
};
Okee-dokee.
And even if you could, you still wouldn't have the perl-style behavior that
I described. If you tried:
x["root"]["branch"]["leaf"] = 5;
the compiler would not know how to resolve the second (and third) set of
braces.
Of course it would. It's merely a matter of implementing operator[]()
accordingly.
I think I have something workable. I've made the restriction that you can
only store strings in the leaves. So, instead of the code above, you would
have to do this:
x["root"]["branch"]["leaf"] = "5";
Splendid. That's the first step. Keep going until you've got everything
wrapped up.
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