Re: argument deduction for function template

From:
"Victor Bazarov" <v.Abazarov@comAcast.net>
Newsgroups:
comp.lang.c++
Date:
Thu, 21 Jun 2007 12:31:46 -0400
Message-ID:
<f5e95j$u5v$1@news.datemas.de>
vectorizor wrote:

Hey all,

thanks for the comments. Please find attached a standalone version of
my code. Please forgive the mess, I just did a quick copy and paste of
many files.

I am compiling with VS 2005 and the latest Intel compiler.


This is what your code should look like, distilled:

[..]
typedef float f32;
typedef unsigned char u8;

template <typename T>
struct Image
{
};

template <typename T>
struct GrayImage : public Image<T>
{
};

template <typename T>
struct ColourImage : public Image<T>
{
};

template <typename T, typename U>
void RGB2Log(ColourImage<U> &input, GrayImage<T> &buffer,
               bool linear, T snr)
{
}

int main(int argc, char* argv[])
{
   GrayImage<f32> gray, tmp;
   ColourImage<u8> color;

   RGB2Log(color, gray, true, 1.0);


Here you pass 'GrayImage<f32>' as the second argument from which
'T' is deduced as 'f32' or 'float'. _And_ you pass 1.0 (a double
literal) as the fourth argument, from which 'T' is deduced as...
'double' ! Do you not see it in the error message?

Now , if you want '1.0' to be treated as 'f32', you need to cast
it to 'f32':

        RGB2Log(color, gray, true, (f32) 1.0);

}

##### CUT #####


V
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